HP 35s User Manual

 
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HP 35s  Base conversions and arithmetic 
 
hp calculators - 3 - HP 35s  Base conversions and arithmetic - Version 1.0 
Answer: 7640 base 8. Figure 2 shows the result in algebraic mode. 
 
Example 2: Add 7F6 base 16 to 1011001 base 2 and display the result in base 10. 
 
Solution: First, make sure the calculator is in HEX mode to enter the base 16 number.  
 
 $%+ 
  
 In RPN mode (note that  enters the hexadecimal digit F) 
 
 ,-$%-
$%(
&)&&))&$%.
$%&
/ 
 
 In algebraic mode:...

 
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HP 35s  Base conversions and arithmetic 
 
hp calculators - 4 - HP 35s  Base conversions and arithmetic - Version 1.0 
 
 Figure 5 
 
Answer: The result is 2,092,545. Figure 5 shows the result in algebraic mode. 
 
Example 4: Subtract 42 base 8 from 101111 base 2 and then display the twos complement of the result in base 2. 
 
Solution: First, make sure the calculator is in BIN mode to enter the base 2 number. 
 
 $%( 
 
 In RPN mode: 
 
 &)&&&&$%.$%*
(+$%,$%(23 
  
 In algebraic...

 
 
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HP 35s  Using the LOGIC functions 
 
 
 
 
Numbers in different bases 
 
Operations on binary numbers  
 
Practice manipulating binary numbers 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
   

 
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HP 35s  Using the LOGIC functions 
 
hp calculators - 2 - HP 35s  Using the LOGIC functions - Version 1.1 
Numbers in different bases 
 
Most numbers we work with day-to-day are in base 10. There are applications within the computer world that require the 
use of numbers in other bases. The number 24 in base 10 can be translated into base 16 by the following procedure. 
Just as each digit’s location in base 10 can be thought of as a power of ten (the ones’ place, the tens’ place, the...

 
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HP 35s  Using the LOGIC functions 
 
hp calculators - 3 - HP 35s  Using the LOGIC functions - Version 1.1 
The NOT function creates a new binary number where each bit position’s value has been “flipped”, with each 1 becoming 
a 0 and each 0 becoming a 1. This is referred to as the ones complement of the argument.  
 
The NAND function creates a new binary number from two input binary numbers where each bit position’s value is based 
upon a NOT (x AND y). In essence, it returns a bit...

 
hp calculators 
 
HP 35s  Using the LOGIC functions 
 
hp calculators - 4 - HP 35s  Using the LOGIC functions - Version 1.1 
 In algebraic mode, press: 
 
 $>(#
#)$%!%&)%!&#
 
 Figure 6 
 
 
 Figure 7 
 
Answer: 77714 base 8. Figure 6 shows the result in RPN mode. Figure 7 shows the result in algebraic mode.  
 
Example 3:  Perform an NOR on these two binary numbers: #1011 b and #1001 b. Make sure the calculator is in 
BINARY mode to enter the base 2 numbers. Do not forget to append the “b” suffix to...

 
 
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HP 35s  Using the formula solver – part 1 
 
 
 
 
What is a solution? 
 
Practice Example: Finding roots of polynomials 
 
Practice Example: Finding the root of a log equation 
 
Practice Example: Where there is no solution 
 
What the solver can and can not find 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
   

 
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HP 35s  Using the formula solver – part 1 
 
hp calculators - 2 - HP 35s  Using the formula solver – part 1- Version 1.0 
What is a solution? 
 
Given a formula or equation such as: 
 
7x + 12 = 33 
 
it is easy to find that: 
 
x = 3 
 
This is the solution or root of the formula. It answers the question “What value of x makes the formula correct?” 
 
It is rarely this easy to solve a formula or equation. For example look at this one: 
 
4x² - 14LOG(x) = 33 
 
It seems likely that...

 
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HP 35s  Using the formula solver – part 1 
 
hp calculators - 3 - HP 35s  Using the formula solver – part 1- Version 1.0 
 Enter the equation by typing: 
  
 $()*%+,$(-*./,$012))3 
  
 To enter a variable into an equation, press the  key and then one of the letter keys. As with #, 
the symbol A..Z at the top of the screen is shown as a signal that one of the keys marked A through Z must 
be pressed. To enter the variable X in this formula press the % key again. 
  
 To solve the...

 
hp calculators 
 
HP 35s  Using the formula solver – part 1 
 
hp calculators - 4 - HP 35s  Using the formula solver – part 1- Version 1.0 
 Figure 4 
 
 To solve the equation, press 4, then press % again to show that the formula is to be solved for 
X. 
  
 Figure 5 
  
Answer: X = -11 is a second solution of the equation. There is a third solution, or root, which can be found if a 
suitable guess is tried. 
 
Practice Example: Finding the Root of a Log Equation  
 
Example 3: Polynomial equations of...